Hello Michael,

Here is a modified extract from my *.pro file. Since my reference transcript length is 1688bp, and the covered fraction as shown, the actual covered length of the transcript comes to 588bp (am I right there?).

locustranscript_IDlengthexpressed fractionexpressed numbersequenced fractionsequenced numbercovered fraction
Chr1:3631-5899WAT1G01010.116882.0002340273812036E-6102.6374959613343093E-680.348341226577759

 

My read headers from the given transcript are:

@Chr1:3631-5899W:AT1G01010.1:2:1688:10:276/1
@Chr1:3631-5899W:AT1G01010.1:2:1688:10:276/2
@Chr1:3631-5899W:AT1G01010.1:3:1688:1134:1342/1
@Chr1:3631-5899W:AT1G01010.1:3:1688:1134:1342/2
@Chr1:3631-5899W:AT1G01010.1:4:1688:886:1144/1
@Chr1:3631-5899W:AT1G01010.1:4:1688:886:1144/2
@Chr1:3631-5899W:AT1G01010.1:5:1688:1340:1686/1
@Chr1:3631-5899W:AT1G01010.1:5:1688:1340:1686/2

 

My questions are:

 

 

Thanks for your time and help.